∛125 + ∛27 × ³log 3 = ...
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》Bentuk Akar
& Logaritma
= ³√125 + ³√27 × ³ log 3
= ³√5³ + ³√3³ × 1
= 5 + 3 × 1
= 8
-:-:-
Penjelasan dengan langkah-langkah:
∛125 + ∛27 × ³log 3
= 125^1/3 + 27^1/3 × ³^1 log 3¹
= (5³)^⅓ + (3³)^⅓ × 1/1 × 1. ³log 3
= 5 + 3 × 1/1 × ³log 3
= 5 + 3 × 1
= 8
